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5a^2+12a-1=5a
We move all terms to the left:
5a^2+12a-1-(5a)=0
We add all the numbers together, and all the variables
5a^2+7a-1=0
a = 5; b = 7; c = -1;
Δ = b2-4ac
Δ = 72-4·5·(-1)
Δ = 69
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-\sqrt{69}}{2*5}=\frac{-7-\sqrt{69}}{10} $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+\sqrt{69}}{2*5}=\frac{-7+\sqrt{69}}{10} $
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